3.15.74 \(\int \frac {(a^2+2 a b x+b^2 x^2)^2}{(d+e x)^5} \, dx\) [1474]

Optimal. Leaf size=111 \[ -\frac {(b d-a e)^4}{4 e^5 (d+e x)^4}+\frac {4 b (b d-a e)^3}{3 e^5 (d+e x)^3}-\frac {3 b^2 (b d-a e)^2}{e^5 (d+e x)^2}+\frac {4 b^3 (b d-a e)}{e^5 (d+e x)}+\frac {b^4 \log (d+e x)}{e^5} \]

[Out]

-1/4*(-a*e+b*d)^4/e^5/(e*x+d)^4+4/3*b*(-a*e+b*d)^3/e^5/(e*x+d)^3-3*b^2*(-a*e+b*d)^2/e^5/(e*x+d)^2+4*b^3*(-a*e+
b*d)/e^5/(e*x+d)+b^4*ln(e*x+d)/e^5

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Rubi [A]
time = 0.06, antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {27, 45} \begin {gather*} \frac {4 b^3 (b d-a e)}{e^5 (d+e x)}-\frac {3 b^2 (b d-a e)^2}{e^5 (d+e x)^2}+\frac {4 b (b d-a e)^3}{3 e^5 (d+e x)^3}-\frac {(b d-a e)^4}{4 e^5 (d+e x)^4}+\frac {b^4 \log (d+e x)}{e^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a^2 + 2*a*b*x + b^2*x^2)^2/(d + e*x)^5,x]

[Out]

-1/4*(b*d - a*e)^4/(e^5*(d + e*x)^4) + (4*b*(b*d - a*e)^3)/(3*e^5*(d + e*x)^3) - (3*b^2*(b*d - a*e)^2)/(e^5*(d
+ e*x)^2) + (4*b^3*(b*d - a*e))/(e^5*(d + e*x)) + (b^4*Log[d + e*x])/e^5

Rule 27

Int[(u_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[u*Cancel[(b/2 + c*x)^(2*p)/c^p], x] /; Fr
eeQ[{a, b, c}, x] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^5} \, dx &=\int \frac {(a+b x)^4}{(d+e x)^5} \, dx\\ &=\int \left (\frac {(-b d+a e)^4}{e^4 (d+e x)^5}-\frac {4 b (b d-a e)^3}{e^4 (d+e x)^4}+\frac {6 b^2 (b d-a e)^2}{e^4 (d+e x)^3}-\frac {4 b^3 (b d-a e)}{e^4 (d+e x)^2}+\frac {b^4}{e^4 (d+e x)}\right ) \, dx\\ &=-\frac {(b d-a e)^4}{4 e^5 (d+e x)^4}+\frac {4 b (b d-a e)^3}{3 e^5 (d+e x)^3}-\frac {3 b^2 (b d-a e)^2}{e^5 (d+e x)^2}+\frac {4 b^3 (b d-a e)}{e^5 (d+e x)}+\frac {b^4 \log (d+e x)}{e^5}\\ \end {align*}

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Mathematica [A]
time = 0.04, size = 119, normalized size = 1.07 \begin {gather*} \frac {\frac {(b d-a e) \left (3 a^3 e^3+a^2 b e^2 (7 d+16 e x)+a b^2 e \left (13 d^2+40 d e x+36 e^2 x^2\right )+b^3 \left (25 d^3+88 d^2 e x+108 d e^2 x^2+48 e^3 x^3\right )\right )}{(d+e x)^4}+12 b^4 \log (d+e x)}{12 e^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a^2 + 2*a*b*x + b^2*x^2)^2/(d + e*x)^5,x]

[Out]

(((b*d - a*e)*(3*a^3*e^3 + a^2*b*e^2*(7*d + 16*e*x) + a*b^2*e*(13*d^2 + 40*d*e*x + 36*e^2*x^2) + b^3*(25*d^3 +
88*d^2*e*x + 108*d*e^2*x^2 + 48*e^3*x^3)))/(d + e*x)^4 + 12*b^4*Log[d + e*x])/(12*e^5)

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Maple [A]
time = 0.64, size = 184, normalized size = 1.66

method	result	size
risch	\(\frac {-\frac {4 b^{3} \left (a e -b d \right ) x^{3}}{e^{2}}-\frac {3 b^{2} \left (a^{2} e^{2}+2 a b d e -3 b^{2} d^{2}\right ) x^{2}}{e^{3}}-\frac {2 b \left (2 e^{3} a^{3}+3 a^{2} b d \,e^{2}+6 a \,b^{2} d^{2} e -11 b^{3} d^{3}\right ) x}{3 e^{4}}-\frac {3 e^{4} a^{4}+4 a^{3} b d \,e^{3}+6 a^{2} b^{2} d^{2} e^{2}+12 a \,b^{3} d^{3} e -25 b^{4} d^{4}}{12 e^{5}}}{\left (e x +d \right )^{4}}+\frac {b^{4} \ln \left (e x +d \right )}{e^{5}}\)	\(176\)
norman	\(\frac {-\frac {3 e^{4} a^{4}+4 a^{3} b d \,e^{3}+6 a^{2} b^{2} d^{2} e^{2}+12 a \,b^{3} d^{3} e -25 b^{4} d^{4}}{12 e^{5}}-\frac {4 \left (e a \,b^{3}-d \,b^{4}\right ) x^{3}}{e^{2}}-\frac {3 \left (a^{2} b^{2} e^{2}+2 a \,b^{3} d e -3 b^{4} d^{2}\right ) x^{2}}{e^{3}}-\frac {2 \left (2 a^{3} b \,e^{3}+3 a^{2} b^{2} d \,e^{2}+6 d^{2} e a \,b^{3}-11 b^{4} d^{3}\right ) x}{3 e^{4}}}{\left (e x +d \right )^{4}}+\frac {b^{4} \ln \left (e x +d \right )}{e^{5}}\)	\(182\)
default	\(-\frac {4 b \left (e^{3} a^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right )}{3 e^{5} \left (e x +d \right )^{3}}-\frac {4 b^{3} \left (a e -b d \right )}{e^{5} \left (e x +d \right )}-\frac {3 b^{2} \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right )}{e^{5} \left (e x +d \right )^{2}}+\frac {b^{4} \ln \left (e x +d \right )}{e^{5}}-\frac {e^{4} a^{4}-4 a^{3} b d \,e^{3}+6 a^{2} b^{2} d^{2} e^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}}{4 e^{5} \left (e x +d \right )^{4}}\)	\(184\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^5,x,method=_RETURNVERBOSE)

[Out]

-4/3*b/e^5*(a^3*e^3-3*a^2*b*d*e^2+3*a*b^2*d^2*e-b^3*d^3)/(e*x+d)^3-4*b^3/e^5*(a*e-b*d)/(e*x+d)-3*b^2/e^5*(a^2*
e^2-2*a*b*d*e+b^2*d^2)/(e*x+d)^2+b^4*ln(e*x+d)/e^5-1/4*(a^4*e^4-4*a^3*b*d*e^3+6*a^2*b^2*d^2*e^2-4*a*b^3*d^3*e+
b^4*d^4)/e^5/(e*x+d)^4

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Maxima [A]
time = 0.30, size = 206, normalized size = 1.86 \begin {gather*} b^{4} e^{\left (-5\right )} \log \left (x e + d\right ) + \frac {25 \, b^{4} d^{4} - 12 \, a b^{3} d^{3} e - 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} - 3 \, a^{4} e^{4} + 48 \, {\left (b^{4} d e^{3} - a b^{3} e^{4}\right )} x^{3} + 36 \, {\left (3 \, b^{4} d^{2} e^{2} - 2 \, a b^{3} d e^{3} - a^{2} b^{2} e^{4}\right )} x^{2} + 8 \, {\left (11 \, b^{4} d^{3} e - 6 \, a b^{3} d^{2} e^{2} - 3 \, a^{2} b^{2} d e^{3} - 2 \, a^{3} b e^{4}\right )} x}{12 \, {\left (x^{4} e^{9} + 4 \, d x^{3} e^{8} + 6 \, d^{2} x^{2} e^{7} + 4 \, d^{3} x e^{6} + d^{4} e^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^5,x, algorithm="maxima")

[Out]

b^4*e^(-5)*log(x*e + d) + 1/12*(25*b^4*d^4 - 12*a*b^3*d^3*e - 6*a^2*b^2*d^2*e^2 - 4*a^3*b*d*e^3 - 3*a^4*e^4 +
48*(b^4*d*e^3 - a*b^3*e^4)*x^3 + 36*(3*b^4*d^2*e^2 - 2*a*b^3*d*e^3 - a^2*b^2*e^4)*x^2 + 8*(11*b^4*d^3*e - 6*a*
b^3*d^2*e^2 - 3*a^2*b^2*d*e^3 - 2*a^3*b*e^4)*x)/(x^4*e^9 + 4*d*x^3*e^8 + 6*d^2*x^2*e^7 + 4*d^3*x*e^6 + d^4*e^5
)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 251 vs. \(2 (111) = 222\).
time = 3.97, size = 251, normalized size = 2.26 \begin {gather*} \frac {25 \, b^{4} d^{4} - {\left (48 \, a b^{3} x^{3} + 36 \, a^{2} b^{2} x^{2} + 16 \, a^{3} b x + 3 \, a^{4}\right )} e^{4} + 4 \, {\left (12 \, b^{4} d x^{3} - 18 \, a b^{3} d x^{2} - 6 \, a^{2} b^{2} d x - a^{3} b d\right )} e^{3} + 6 \, {\left (18 \, b^{4} d^{2} x^{2} - 8 \, a b^{3} d^{2} x - a^{2} b^{2} d^{2}\right )} e^{2} + 4 \, {\left (22 \, b^{4} d^{3} x - 3 \, a b^{3} d^{3}\right )} e + 12 \, {\left (b^{4} x^{4} e^{4} + 4 \, b^{4} d x^{3} e^{3} + 6 \, b^{4} d^{2} x^{2} e^{2} + 4 \, b^{4} d^{3} x e + b^{4} d^{4}\right )} \log \left (x e + d\right )}{12 \, {\left (x^{4} e^{9} + 4 \, d x^{3} e^{8} + 6 \, d^{2} x^{2} e^{7} + 4 \, d^{3} x e^{6} + d^{4} e^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^5,x, algorithm="fricas")

[Out]

1/12*(25*b^4*d^4 - (48*a*b^3*x^3 + 36*a^2*b^2*x^2 + 16*a^3*b*x + 3*a^4)*e^4 + 4*(12*b^4*d*x^3 - 18*a*b^3*d*x^2
- 6*a^2*b^2*d*x - a^3*b*d)*e^3 + 6*(18*b^4*d^2*x^2 - 8*a*b^3*d^2*x - a^2*b^2*d^2)*e^2 + 4*(22*b^4*d^3*x - 3*a
*b^3*d^3)*e + 12*(b^4*x^4*e^4 + 4*b^4*d*x^3*e^3 + 6*b^4*d^2*x^2*e^2 + 4*b^4*d^3*x*e + b^4*d^4)*log(x*e + d))/(
x^4*e^9 + 4*d*x^3*e^8 + 6*d^2*x^2*e^7 + 4*d^3*x*e^6 + d^4*e^5)

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 230 vs. \(2 (100) = 200\).
time = 1.70, size = 230, normalized size = 2.07 \begin {gather*} \frac {b^{4} \log {\left (d + e x \right )}}{e^{5}} + \frac {- 3 a^{4} e^{4} - 4 a^{3} b d e^{3} - 6 a^{2} b^{2} d^{2} e^{2} - 12 a b^{3} d^{3} e + 25 b^{4} d^{4} + x^{3} \left (- 48 a b^{3} e^{4} + 48 b^{4} d e^{3}\right ) + x^{2} \left (- 36 a^{2} b^{2} e^{4} - 72 a b^{3} d e^{3} + 108 b^{4} d^{2} e^{2}\right ) + x \left (- 16 a^{3} b e^{4} - 24 a^{2} b^{2} d e^{3} - 48 a b^{3} d^{2} e^{2} + 88 b^{4} d^{3} e\right )}{12 d^{4} e^{5} + 48 d^{3} e^{6} x + 72 d^{2} e^{7} x^{2} + 48 d e^{8} x^{3} + 12 e^{9} x^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b**2*x**2+2*a*b*x+a**2)**2/(e*x+d)**5,x)

[Out]

b**4*log(d + e*x)/e**5 + (-3*a**4*e**4 - 4*a**3*b*d*e**3 - 6*a**2*b**2*d**2*e**2 - 12*a*b**3*d**3*e + 25*b**4*
d**4 + x**3*(-48*a*b**3*e**4 + 48*b**4*d*e**3) + x**2*(-36*a**2*b**2*e**4 - 72*a*b**3*d*e**3 + 108*b**4*d**2*e
**2) + x*(-16*a**3*b*e**4 - 24*a**2*b**2*d*e**3 - 48*a*b**3*d**2*e**2 + 88*b**4*d**3*e))/(12*d**4*e**5 + 48*d*
*3*e**6*x + 72*d**2*e**7*x**2 + 48*d*e**8*x**3 + 12*e**9*x**4)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 279 vs. \(2 (111) = 222\).
time = 1.46, size = 279, normalized size = 2.51 \begin {gather*} -b^{4} e^{\left (-5\right )} \log \left (\frac {{\left | x e + d \right |} e^{\left (-1\right )}}{{\left (x e + d\right )}^{2}}\right ) + \frac {1}{12} \, {\left (\frac {48 \, b^{4} d e^{15}}{x e + d} - \frac {36 \, b^{4} d^{2} e^{15}}{{\left (x e + d\right )}^{2}} + \frac {16 \, b^{4} d^{3} e^{15}}{{\left (x e + d\right )}^{3}} - \frac {3 \, b^{4} d^{4} e^{15}}{{\left (x e + d\right )}^{4}} - \frac {48 \, a b^{3} e^{16}}{x e + d} + \frac {72 \, a b^{3} d e^{16}}{{\left (x e + d\right )}^{2}} - \frac {48 \, a b^{3} d^{2} e^{16}}{{\left (x e + d\right )}^{3}} + \frac {12 \, a b^{3} d^{3} e^{16}}{{\left (x e + d\right )}^{4}} - \frac {36 \, a^{2} b^{2} e^{17}}{{\left (x e + d\right )}^{2}} + \frac {48 \, a^{2} b^{2} d e^{17}}{{\left (x e + d\right )}^{3}} - \frac {18 \, a^{2} b^{2} d^{2} e^{17}}{{\left (x e + d\right )}^{4}} - \frac {16 \, a^{3} b e^{18}}{{\left (x e + d\right )}^{3}} + \frac {12 \, a^{3} b d e^{18}}{{\left (x e + d\right )}^{4}} - \frac {3 \, a^{4} e^{19}}{{\left (x e + d\right )}^{4}}\right )} e^{\left (-20\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^5,x, algorithm="giac")

[Out]

-b^4*e^(-5)*log(abs(x*e + d)*e^(-1)/(x*e + d)^2) + 1/12*(48*b^4*d*e^15/(x*e + d) - 36*b^4*d^2*e^15/(x*e + d)^2
+ 16*b^4*d^3*e^15/(x*e + d)^3 - 3*b^4*d^4*e^15/(x*e + d)^4 - 48*a*b^3*e^16/(x*e + d) + 72*a*b^3*d*e^16/(x*e +
d)^2 - 48*a*b^3*d^2*e^16/(x*e + d)^3 + 12*a*b^3*d^3*e^16/(x*e + d)^4 - 36*a^2*b^2*e^17/(x*e + d)^2 + 48*a^2*b
^2*d*e^17/(x*e + d)^3 - 18*a^2*b^2*d^2*e^17/(x*e + d)^4 - 16*a^3*b*e^18/(x*e + d)^3 + 12*a^3*b*d*e^18/(x*e + d
)^4 - 3*a^4*e^19/(x*e + d)^4)*e^(-20)

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Mupad [B]
time = 0.61, size = 213, normalized size = 1.92 \begin {gather*} \frac {b^4\,\ln \left (d+e\,x\right )}{e^5}-\frac {\frac {3\,a^4\,e^4+4\,a^3\,b\,d\,e^3+6\,a^2\,b^2\,d^2\,e^2+12\,a\,b^3\,d^3\,e-25\,b^4\,d^4}{12\,e^5}+\frac {3\,x^2\,\left (a^2\,b^2\,e^2+2\,a\,b^3\,d\,e-3\,b^4\,d^2\right )}{e^3}+\frac {2\,x\,\left (2\,a^3\,b\,e^3+3\,a^2\,b^2\,d\,e^2+6\,a\,b^3\,d^2\,e-11\,b^4\,d^3\right )}{3\,e^4}+\frac {4\,b^3\,x^3\,\left (a\,e-b\,d\right )}{e^2}}{d^4+4\,d^3\,e\,x+6\,d^2\,e^2\,x^2+4\,d\,e^3\,x^3+e^4\,x^4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a^2 + b^2*x^2 + 2*a*b*x)^2/(d + e*x)^5,x)

[Out]

(b^4*log(d + e*x))/e^5 - ((3*a^4*e^4 - 25*b^4*d^4 + 6*a^2*b^2*d^2*e^2 + 12*a*b^3*d^3*e + 4*a^3*b*d*e^3)/(12*e^
5) + (3*x^2*(a^2*b^2*e^2 - 3*b^4*d^2 + 2*a*b^3*d*e))/e^3 + (2*x*(2*a^3*b*e^3 - 11*b^4*d^3 + 3*a^2*b^2*d*e^2 +
6*a*b^3*d^2*e))/(3*e^4) + (4*b^3*x^3*(a*e - b*d))/e^2)/(d^4 + e^4*x^4 + 4*d*e^3*x^3 + 6*d^2*e^2*x^2 + 4*d^3*e*
x)

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